Nikhil Paul will provide lecture notes on a particular type of
exam question up to this point...


Continuing:


struct Point_S
{
  double x;
  double y;
};

int main(int argc, char *argv[])
{

   Point_S p;
   Point_S *q;
   Point_S *r;

   q = new Point_S;
   q->x = 3.0; q->y = 2.0
   p.x = 1.0; p.y = 2.5;
   r = &p;   
   ...
}

Recall that 
   a->b is a shorthand notation for (*a).b
   implicitly, the left operand must be a pointer, and you are dereferencing it
 
expr      type		

p	  Point_S
&p	  Point_S *
*p	  error	  
p.x	  double
p->x	  error
p.y	  double
(*p).y	  error
q->y	  double  
&((*q).y) double *
q.x	  error 
q->x	  double
q.y	  error
(*q).y	  double
q->y	  double

expr	  stack/heap/error
==========================
p	  stack
*p	  error
p.x	  stack
*q	  heap
q->y	  heap
q.x	  error
(*q).x	  heap

	  type		stack/heap/error
argc	 int		stack	
*argc	 error		error
&argc	 int *		[N/A]
argv	 char **	stack
*argv	 char *		[I won't ask: static area? stack?]
&argv	 char ***	[I won't ask]
argv[0]	 char * 		[I won't ask]
argv[0][2] char		[I won't ask]