Lecture Notes for November 5, 2004

I give Dr. Conrad to use/copy/correct these notes.
If you have any questions about my notes, please e-mail me: KVoit@udel.edu

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General Notes:

Exam next Wednesday
Project 2 Description – 
- Is posted online
- Due 2 weeks from today
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What is the output? (Never answered)

void p (int a, int b)
{
  int i, j;
  for (i = 0; i<a; i++)
    {
      for(j = 0; j<b; j++)
	printf("o");
      printf("\n");
    }
}

[Postscript from P. Conrad 12/01/04: Try calling this with p(3,4),
for example; what is the output?   The main program is provided
in this directory.]

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Write a function with 4 parameters: array, size, of array, min and max.
	[Handout was given]


void minAndMax(int array[], int *min, int *max, int size)
{
  int i;
  (*min) = array[0];
  (*max) = array[0];
  for(i = 1; i<size; i++)
    {
      if (array [i] > (*max))
	(*max) = array [i];
      if(array [i] < (*min))
	    (*min) = array [i];
    }
}

[Postscript from P. Conrad, 12/01/04: a main program to test this
called p2.c is in the companion directory]

Declare an array: the first 5 prime numbers. (Where 1 is neither prime nor composite.) Then call minMax on array and print results.

int main(void)
{
  int array1 [5] = {2,3,5,7,11};
  int a,b;
  minAndMax(array1,&a,&b,5);
  printf("min is %d, max is %d \n",a,b);
  return(0);
}

[Postscript from P. Conrad, 12/01/04: This program is 
called p3.c is in the companion directory]


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For each of the parameters indicate: call by value or call by reference?

array: call by reference (Always!)
min: call by reference
max: call by reference
size: call by value

Name of array = name of pointer = address

If an array has 4 elements, they are numbered:

array [0]
array [1]
array [2]
array [3]

Total size = 4